Anilrgowda

Question: OS: Linux
Type: Shell Script

I have a CSV file in the following format.
'112'|1|'1480196'|15||'A'
'112'|1|'1481645'|15||'A'
'145'|1|'1492362'|15||'A'
'145'|1|'15103891'|15||'A'
'157'|1|'1536122'|15||'A'
'157'|1|'1537942'|15||'A'
'168'|1|'1587454'|15||'A'
'168'|1|'1596169'|15||'A'

From the above file, I would like to grep the rows with first column '145' and write them to a different file, can someone give me a script to do that.

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Anilrgowda

as wc does not have a option to skip the filename in the output you need to use cat :-(

$( wc -l $2.$$ ) should become $( cat $2.$$ | wc -l ) an no filename should be printed.

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